问题描述

搜索输入框中，只当用户停止输入后，才进行后续的操作，比如发起Http请求等。

学过电子电路的同学应该知道按键防抖。原理是一样的：就是说当调用动作n毫秒后，才会执行该动作，若在这n毫秒内又调用此动作则将重新计算执行时间。本文将分别探讨在angular.js和vue.js中如何实现对用户输入的防抖。

angular.js中解决方案

把去抖函数写成一个service，方便多处调用：

.factory('debounce', ['$timeout','$q', function($timeout, $q) {
    // The service is actually this function, which we call with the func
    // that should be debounced and how long to wait in between calls
    return function debounce(func, wait, immediate) {
      var timeout;
      // Create a deferred object that will be resolved when we need to
      // actually call the func
      var deferred = $q.defer();
      return function() {
        var context = this, args = arguments;
        var later = function() {
          timeout = null;
          if(!immediate) {
            deferred.resolve(func.apply(context, args));
            deferred = $q.defer();
          }
        };
        var callNow = immediate && !timeout;
        if ( timeout ) {
          $timeout.cancel(timeout);
        }
        timeout = $timeout(later, wait);
        if (callNow) {
          deferred.resolve(func.apply(context,args));
          deferred = $q.defer();
        }
        return deferred.promise;
      };
    };
  }])

调用方法，在需要使用该功能的controller/directive中注入debounce，也要注入$watch,然后：

$scope.$watch('searchText',debounce(function (newV, oldV) {
   console.log(newV, oldV);
   if (newV !== oldV) {
       $scope.getDatas(newV);
   }
}, 350));

大功告成！

Vue.js中的解决方案

首先在公共函数文件中注册debounce

export function debounce(func, delay) {
  let timer

  return function (...args) {
    if (timer) {
      clearTimeout(timer)
    }
    timer = setTimeout(() => {
      func.apply(this, args)
    }, delay)
  }
}

然后在需要使用的组件中引入debounce，并且在created生命周期内调用：

created() {
  this.$watch('searchText', debounce((newSearchText) => {
    this.getDatas(newSearchText)
  }, 200))
}

大功告成！

来源：https://segmentfault.com/a/1190000012751237

链接: https://www.fly63.com/article/detial/339